What
is a quadratic equation?
A quadratic equation is an equation
that can be written in this form.
ax2+bx+c=0
The a,b, and c here represent real
number coefficients. So this means
we are talking about an equation that
is a constant times the variable squared
plus a constant times the variable
plus a constant equals zero, where
the coefficient a on the variable
squared can't be zero, because if
it were then it would be a linear
equation.
Examples
2x2+3x+1=0, x2+x=2x+3,
(x+2)(x+3)=5
All these equations are equivalent
to equations of the above form. The
first one is already in that form.
The second one can be put into it
by subtracting 2x+3 from both sides.
The third one can be put into it by
multiplying out and then subtracting
5 from both sides.
Standard
Form
The form
ax2+bx+c=0
is the standard form for a quadratic
equation, and for future reference,
here the letter a will always mean
the coefficient on the square of the
variable, and b will be the coefficient
on the variable, and c will be the
constant term. To get a quadratic
into standard form you must remove
all parentheses and combine all like
terms and add or subtract something
from both sides so that the right
side will be zero. Once you have your
equation in standard form you can
identify a,b, and c.
Example
This and many of the other examples
below are from my MathHelp collection
of problem sets, Quadratic Equations.
For more practice and worked out examples
for this or any other techniques explained
here, click on the MathHelp link at
the bottom of the page.
Problem: Write the equation in standard
form and identify a,b, and c.
Solution: Multiply the left side out
and then subtract the 5 from both
sides.
Solving
Now lets talk about solving these equations.
Quadratic equations are harder to
solve than linear equations, because
once you have them in standard form
it is hard to simplify them any further,
and in this form there are still two
occurrences of the variable, so it's
hard to see what we can do to get
the variable alone.
So we have to find some clever tricks
to get around this problem.
Solving
by Factoring
One trick is to solve the equation by
factoring. This trick works because
of the principle of zero products. The
principle of zero products says
If A and B
are real numbers and AB=0, then either
A=0 or B=0.
This is a very special property that
only zero has. For other numbers there
are lots of ways to multiply and get
them, but not for zero. For zero,
the only way to multiply numbers and
get it, is if one of the numbers is
zero.
The principle of zero products allows
us to reduce a complicated equation
to simpler equations provided the
right side of the equation is zero,
and the equation is factored, because
we can set each of the factors equal
to zero.
- To solve a quadratic by factoring,
first you must make sure it is in
standard form. It
is especially important that it
is set equal to zero,
because remember, the principle
of zero products only works for
zero.
- Then you must factor the left
side.
- Then you set each of your factors
equal to zero and solve the equations
you get to find the solutions to
your equation.
Example
Problem: Solve the equation.
Solution:
The second line here comes from setting
x+1 and x+6 equal to 0 by the principle
of zero factors.
What
if you can't factor?
But some quadratics are difficult to
factor, so for these equations we need
other methods. The method of completing
the square is a method that will work
for any quadratic, but it is a little
bit complicated, so I will introduce
it slowly and step by step. But first
to give you an overview of where we
are going, I will show you a simple
example of it.
Consider the following equation.
x2-2x-1=0
This looks like a nice simple friendly
equation, but we can't solve it by
factoring, because we can't find two
numbers to multiply and get -1 and
add and get -2, so we are going to
have to find another method.
But if only that minus sign on the
1 weren't there, then we could factor
it really easily, in fact it would
be a perfect square. How can we make
that minus sign go away?
Well, one thing we could do is add
2 to both sides of the equation, and
then the equation would become
x2-2x+1=2
and this factors to
(x-1)2=2
Now, I know what you're saying. You
are saying, "But you said that you
have to get it set equal to 0 to solve
it by factoring, because the principle
of zero products only works for 0.
What good does it do to have something
factored and set equal to 2?"
And if you are saying this to yourself,
you are absolutely right. But this
isn't just any old factorization.
It is a perfect
square, and maybe you can
do something with a perfect square
set equal to 2.
If we could figure out how to solve
equations like
(x-1)2=2
that is, perfect squares set equal
to numbers, then we could solve an
equation like
x2-2x-1=0.
And if we could find a way to add
a number to both sides of other quadratics
so that we can put them into the form
perfect square equals constant, then
maybe we could be able to solve them
too.
This means that to help us solve
quadratic equations, we need to learn
two skills.
- Solve equations of the
form (x+k)2=d,
where k and d are numbers.
- Find a way of figuring
out what number to add
to both sides of a quadratic
equations so that the
left side will become
a perfect square.
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To work our way up to the task of
solving equations of the form
(x+k)2=d
let's first start with the slightly
easier task of solving equation of
the form
x2=d
How do we solve an equation of the
form
x2=d?
If x is greater than 0 then the obvious
answer is
but this is not quite right because
it only gives you the positive square
root of d, and all positive numbers
have two square roots, a positive
one and a negative one. So to be sure
that you are getting all solutions
to an equation of this form, your
answer must be
If x less than 0 then what happens?
What kind of number can you square
and get a negative number? If you
square a positive number then clearly
you get a positive number. But if
you square a negative number then
you have a product of two negative
numbers, so you still get a positive
number. So what is left for squaring
and getting a negative number? Nothing.
So the equation has no solutions.
Now let's look at the more general
equation of the form
(x+k)2=d
This is really not much harder since
anything you can do with x you should
be able to do with x+k. x+k represents
a number too. So solve for x+k and
then add something to both sides of
the equation to get x alone.
Example 1
Problem: Solve the equation.
Solution:
Example 2
Problem: Solve the equation.
Solution: Anything you can do with x,
you can do with x+1, and once you find
x+1 all you have to do to get x is subtract
1.
Completing
the Square
Now to problem number two, that of finding
something to add to a quadratic to make
it a perfect square.
This is what is meant by completing
the square, and the secret to it is
to expand out the expression
(x+k)2
and see what makes perfect squares
tick. Applying our formula for squaring
a binomial, we get
(x+k)2=x2+2kx+k2
The key here is to look at the relationship
between the coefficient on x and the
constant coefficient. The coefficient
on x is 2k and the constant term is
k2. This means that if
we know the coefficient on x, and
we want to know what the constant
term has to be for the expression
to be a perfect square, then we need
to divide the coefficient on x by
2 to get k, and then square to get
k2.
So if you have an expression of the
form
x2+bx
and you want to find something to
add to it to make it a perfect square,
then you need to
- Divide b by 2 to get
k
- Square k to get k2.
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Example
Problem: Complete the square.
Solution:
The yellow part is the scratch paper.
On the scratch paper you first divide
the 9 by 2 and then square the result.
Don't worry about the minus sign, because
it will go away when you square anyway.
Then the number you get will be the
number you need to add to the expression
to make a perfect square out of it.
After you do that it is good practice
to write it as the square that it is.
For that you can use the first line
of your scratch paper and match the
sign with the sign of the second term
of the original expression.
I hope the above has helped you understand
the process of completing the square.
If not, there is another approach
to it that I have written an article
about that you might find interesting
for further understanding. It is a
geometrical approach based on the
method that many earlier mathematician
used. You can read my article A Geometrical
Approach to Completing the Square
to find out about it.
Solving
by Completing the Square
Now we are ready to use the method of
completing the squares to solve quadratic
equations. The best way to do this is
as follows.
- Add something to both
sides so that the left
side has no constant term.
- Figure out what to add
to the left side to make
it a perfect square, and
add that to both sides.
- Write the left side
as the perfect square
that it is and do the
arithmetic on the right
side.
- Solve the equation you
get by the methods of
equations of the form
(x+k)2=d
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One thing we left out. So far all
of the equations we have solved have
had a coefficient of 1 on x2.
What do we do if we have a coefficient
other than 1 on there?
Well, we don't really have any method
of completing the squares to deal
with that situation, so the easiest
thing to do is just divide both sides
by it and put up with the fractions.
With completing the squares, fractions
are not so bad to deal with because
there is no guess work.
Example
Problem: Solve the equation.
Solution:
First we divide both sides of the equation
by 2, to get a coefficient of 1 on the
first term. 0/2 is still 0. Then we
add 1/2 to both sides so that it is
easier to figure out what to add to
make the left side a perfect square.
Then we complete the square in order
to figure out what to add to both sides
to make the left side a perfect square.
The scratch work for this is shown in
yellow. The best way to divide a fraction
by 2 is to multiply it by 1/2. Then
we write the left side as the perfect
square that it is, and do the arithmetic
on the right side. Now take square roots
and add 3/4 to both sides to get the
final answer.
The
Quadratic Formula
Now that you have learned the method
of completing the squares, I will tell
you a secret. The methods of completing
the squares is such a good method for
solving quadratics that it is very seldom
used for it. It is used for other things
in mathematics. See my article
Equations
of Circles for another use
for it. But for solving quadratic equations,
it is such a good method that it puts
itself out of business.
You see, with such a mechanical method
like the method of completing the
squares, why not just apply it to
the general quadratic equation and
solve all quadratics in the world
at once, and be done with it, and
never have to use algebra to solve
a quadratic again.
Problem: Solve the equation:
Solution:
Just do it the same way with the
letters as you did with the numbers.
First divide both sides by a. Then
subtract c/a from both sides to be
able to see more easily what to add
to the left side to make it a perfect
square. Then complete the square on
the scratch paper and add what you
get to both sides. Write the left
side as the perfect square that it
is. Instead of doing arithmetic on
the right side you have to do a little
bit of algebra, using 4a2
as a common denominator. Then take
square roots and subtract b/2a from
both sides and use 2a a common denominator
to get the final answer.
We have just solved all quadratics
in the world at once and derived the
quadratic formula, which says:
For any real numbers a,b, and c,
the solutions to the equation
ax2+bx+c=0
are
Solving
by the Quadratic Formula
Since this formula is somewhat long
and complicated, it is best to evaluate
it in two smaller pieces by first
evaluating the thing inside the radical,
b2-4ac
and then put the result into the
formula
The quantity
b2-4ac
even has a name. It is called the
discriminant. And there is another
advantage to computing it first. Since
it is what is in the radical, it can't
be negative if there are going to
be solutions to the equation, because
you can't take a square root of a
negative number, (unless you use the
imaginary numbers, and we're not yet
ready for them here) so if the discriminant
comes out negative, then you don't
have to do any more work, and all
you have to do is write "no solution"
on your paper and you are done. Sometimes
you can determine this quite quickly
by estimating, particularly if a and
c are very large and b is small.
Example 1
Problem: Solve the equation.
Solution:
Example 2
Problem: Solve the equation.
Solution: No solution. b is -2, which
is very small in comparison to a=6 and
c=27, so you don't even have to compute
the discriminant to see that it is going
to be negative.
Imaginary Solutions
This section is for more advanced students
who know about imaginary numbers. For
a brief introduction see my article
Complex Number
Arithmetic. If you know about imaginary
numbers, you don't have to stop when
you see the square root of a negative
number, because with imaginary numbers
you can take the square root of a negative
number. To find the square root of any
negative number you just take the square
root of the corresponding positive number
and multiply it by i, the square root
of -1. This makes sense at least once
you believe in the idea that the square
root of -1 is i, because of the multiplication
rule for square roots. (See
Square
Roots.)
(It is customary usually to write the
real number after the i when it is a
square root so that it is clear that
the i is not inside the radical.)
Once you know how to find square
roots of negative numbers, you find
imaginary solutions to quadratics
by the completing the square or the
quadratic formula pretty much like
you find real ones. For the following
examples the instruction is to solve
the equation.
Example 1:
x2+2x+5=0
Solution:
Completing
the Square:
Explanation:
First we add -5 to both sides to get
the constant on the right side of the
equation so that it is more clear what
we need to add to the left side to make
it a perfect square. Then we complete
the square. 2/2=1, 1
2=1,
so 1 is the number we add to the left
side to get a perfect square. Whatever
you do to one side of an equation, you
have to do to the other side, so we
also add 1 to the right side of the
equation. Then we write the left side
as the perfect square that it is, and
do the arithmetic on the right side.
In this equation we get a negative number
on the right side, but with imaginary
numbers we can deal with that. The two
square roots of -4 are 2i and -2i, so
x+1 has to be one of them. Then to find
out what x is, all we have to do is
add -1 to both sides.
Quadratic
Formula:
Explanation:
First compute the discriminant and find
its square root. The square root of
-16 is the square root of 16 times i,
4i. Then we just fit in the square root
in its place in the formula. The numerator
has a common factor of 2 that we can
factor out and cancel with the 2 in
the denominator.
Example 2:
x2+x+1=0
Completing
the Square:
Explanation:
Again we first subtract 1 from both
sides so that it is more clear what
we need to add. For the completing the
square part, this time the coefficient
on x is 1. Half of 1 is 1/2 and (1/2)
2=1/4,
so 1/4 is the completing the square
number. We add it to both sides, because
anything you add to one side you have
to add to the other side. Then again
we get a negative number to take plus
and minus square roots of, but we can
handle that with imaginary numbers.
We just break it up into square roots
of -1, 3, and 4. The square root of
-1 is i, the square root of 4 is 2,
and the square root of 3 is the square
root of 3. Then to get the final answer
we add -1/2 to both sides.
Quadratic
Formula:
Explanation:
First we figure out the discriminant,
which comes out to be -3, and then we
take its square root. The square root
of a negative number is just the square
root of the corresponding positive one
times i. This time we can't the square
root of 3 is an irrational number, so
it is better left undone thinking of
radical 3 is the name for the exact
number that you multiply by itself to
get 3. Then after we have found the
square root of -3, we can put it in
place of the radical in the formula
to get our final answer.
Example 3:
3x2+2x+3=0
Completing
the Square:
Explanation:
In this one there is a coefficient other
than 1 on the x
2, namely
3, so first we have to get rid of it
by dividing both sides by 3. Then from
there it is pretty much like the other
examples. Next we add -1 to both sides
to see more clearly what we need to
add to make the left side a perfect
square. The coefficient on x is 2/3.
To find half of 2/3 we multiply it by
1/2 and get 1/3. Then to find the completing
the square number, we square that and
get 1/9, which we add to both sides
of the equation. Then we write the left
side as the perfect square that it is
and do the arithmetic on the right side.
And again since this section is about
imaginary solutions, we get a negative
number on the right side of the equation
to take the square root of. Then after
taking plus and minus square roots,
we add -1/3 to both sides to get the
final answer.
Quadratic
Formula:
Explanation:
First we find the discriminant, and
we get -32. The square root of -32 is
the square root of -1 times the square
root of 16 times the square root of
2. The square root of -1 is i, the square
root of 16 is 4, and the square root
of 2 is something nasty and irrational,
so it is left as the square root of
2. Then we put this square root in place
of the radical in the formula and simplify
to get the final answer.